4x^2-52x+168x=0

Solution for 4x^2-52x+168x=0 equation:

4x^2-52x+168x=0

We add all the numbers together, and all the variables

4x^2+116x=0

a = 4; b = 116; c = 0;
Δ = b2-4ac
Δ = 1162-4·4·0
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(116)-116}{2*4}=\frac{-232}{8}
=-29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(116)+116}{2*4}=\frac{0}{8}
=0
$